7t-4t^2=0

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Solution for 7t-4t^2=0 equation: 



7t-4t^2=0

a = -4; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-4)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-4}=\frac{-14}{-8}
=1+3/4
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-4}=\frac{0}{-8}
=0
$

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